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2 changes: 1 addition & 1 deletion chapter06.tex
Original file line number Diff line number Diff line change
Expand Up @@ -409,7 +409,7 @@ \subsubsection{Case $c=1$}
The median is an optimal choice,
because if $x$ is smaller than the median,
the sum becomes smaller by increasing $x$,
and if $x$ is larger then the median,
and if $x$ is larger than the median,
the sum becomes smaller by decreasing $x$.
Hence, the optimal solution is that $x$
is the median.
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