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RotateImage.java
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69 lines (65 loc) · 1.49 KB
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package implementation;
/**
* 给定一个 n × n 的二维矩阵表示一个图像。
*
* 将图像顺时针旋转 90 度。
*
* 说明:
*
* 你必须在原地旋转图像,这意味着你需要直接修改输入的二维矩阵。请不要使用另一个矩阵来旋转图像。
*
* 示例 1:
*
* 给定 matrix =
* [
* [1,2,3],
* [4,5,6],
* [7,8,9]
* ],
*
* 原地旋转输入矩阵,使其变为:
* [
* [7,4,1],
* [8,5,2],
* [9,6,3]
* ]
* 示例 2:
*
* 给定 matrix =
* [
* [ 5, 1, 9,11],
* [ 2, 4, 8,10],
* [13, 3, 6, 7],
* [15,14,12,16]
* ],
*
* 原地旋转输入矩阵,使其变为:
* [
* [15,13, 2, 5],
* [14, 3, 4, 1],
* [12, 6, 8, 9],
* [16, 7,10,11]
* ]
*/
public class RotateImage {
public void rotate(int[][] matrix) {
int n = matrix.length;
int index = 0;
while (index < n / 2) {
int pre;
int tmp;
for (int i = 0; i < n - 2 * index - 1; i++) {
pre = matrix[index][index + i];
matrix[index][index + i] = matrix[n - index - 1 - i][index];
tmp = matrix[index + i][n - index - 1];
matrix[index + i][n - index - 1] = pre;
pre = tmp;
tmp = matrix[n - index - 1][n - index - 1 - i];
matrix[n - index - 1][n - index - 1 - i] = pre;
pre = tmp;
matrix[n- index - 1 - i][index] = pre;
}
index++;
}
}
}